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The following initial rate data were found for the reaction 2MnO4- + 5H2C2O4 + 6H+ → 2Mn2+ + 10CO2 + 8H2O The following initial rate data were found for the reaction 2MnO<sub>4</sub><sup>-</sup> + 5H<sub>2</sub>C<sub>2</sub>O<sub>4</sub> + 6H<sup>+</sup> → 2Mn<sup>2+</sup> + 10CO<sub>2</sub> + 8H<sub>2</sub>O   -For which order reaction is the half-life of the reaction independent of the initial concentration of the reactant(s) ? A)  zero order B)  first order C)  second order D)  all of these E)  none of these -For which order reaction is the half-life of the reaction independent of the initial concentration of the reactant(s) ?


A) zero order
B) first order
C) second order
D) all of these
E) none of these

F) A) and C)
G) A) and B)

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A general reaction written as 2A + 2B → C + 2D is studied and yields the following data. A general reaction written as 2A + 2B → C + 2D is studied and yields the following data.   -What is the numerical value of the rate constant? A)  4.00 × 10<sup>-1</sup> B)  4.00 × 10<sup>-2</sup> C)  4.00 × 10<sup>-3</sup> D)  4.00 × 10<sup>-4</sup> E)  none of these -What is the numerical value of the rate constant?


A) 4.00 × 10-1
B) 4.00 × 10-2
C) 4.00 × 10-3
D) 4.00 × 10-4
E) none of these

F) A) and E)
G) B) and E)

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For the reaction CH3CHCH2(g) + HCl(g) → CH3CHClCH3(g) a possible mechanism is For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism. Fast equilibrium For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism. For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism. Fast equilibrium Complex + (HCl)2 For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism. CH3CHClCH3 + 2HCl Slow Derive the rate law for this reaction using this mechanism.

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The following questions refer to the reaction 2A2 + B2 → 2C. The mechanism below has been proposed: The following questions refer to the reaction 2A<sub>2</sub> + B<sub>2</sub> → 2C. The mechanism below has been proposed:   -The activation energy for the reaction H<sub>2</sub>(g)  + I<sub>2</sub>(g)  → 2HI(g)  is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a Pt catalyst. Calculate the value of the ratio rate(catalyzed) /rate(uncatalyzed) . A)  1.00 B)  0.321 C)  1.38 D)  7.62 × 10<sup>10</sup> E)  none of these -The activation energy for the reaction H2(g) + I2(g) → 2HI(g) is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a Pt catalyst. Calculate the value of the ratio rate(catalyzed) /rate(uncatalyzed) .


A) 1.00
B) 0.321
C) 1.38
D) 7.62 × 1010
E) none of these

F) A) and B)
G) A) and C)

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The reaction A → B + C is known to be zero order in A with a rate constant of 4.8 × 10-2 mol/L • s at 25° C. An experiment was run at 25°C where [A]0 = 2.0M. What is the concentration of B after 4.0s?


A) 1.8M
B) 5.5× 10-1 M
C) 2.0M
D) 1.9× 10-1 M
E) 1.1× 10-1 M

F) D) and E)
G) A) and B)

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The following questions refer to the reaction 2A2 + B2 → 2C. The mechanism below has been proposed: The following questions refer to the reaction 2A<sub>2</sub> + B<sub>2</sub> → 2C. The mechanism below has been proposed:   -What is the molecularity of step 2? A)  The molecularity cannot be determined. B)  bimolecular C)  quadmolecular D)  unimolecular E)  termolecular -What is the molecularity of step 2?


A) The molecularity cannot be determined.
B) bimolecular
C) quadmolecular
D) unimolecular
E) termolecular

F) C) and D)
G) D) and E)

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The following questions refer to the hypothetical reaction A + B → products. The kinetics data given can be analyzed to answer the questions. The following questions refer to the hypothetical reaction A + B → products. The kinetics data given can be analyzed to answer the questions.   ​ Determine the magnitude of the pseudo-rate constant (k')  if the magnitude of X in the rate data is 0.00905. A)  0.31 B)  1.81 × 10<sup>-3</sup> C)  4.3 × 10<sup>-3</sup> D)  0.86 E)  1.2 × 10<sup>-2</sup> ​ Determine the magnitude of the pseudo-rate constant (k') if the magnitude of X in the rate data is 0.00905.


A) 0.31
B) 1.81 × 10-3
C) 4.3 × 10-3
D) 0.86
E) 1.2 × 10-2

F) C) and E)
G) B) and C)

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For the reaction A + B → products, the following data were obtained. For the reaction A + B → products, the following data were obtained.   What is the experimental rate law? A)  Rate = k[A]<sup>2</sup>[B] B)  Rate = k[B] C)  Rate = k[A][B] D)  Rate = k[A] E)  Rate = k[A][B] <sup>2</sup> What is the experimental rate law?


A) Rate = k[A]2[B]
B) Rate = k[B]
C) Rate = k[A][B]
D) Rate = k[A]
E) Rate = k[A][B] 2

F) A) and B)
G) C) and D)

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In the reaction 3A(g) + B(g) → 2C(g) + 4D(g) the following data were collected at 100° C. In the reaction 3A(g) + B(g) → 2C(g) + 4D(g) the following data were collected at 100° C.    Let Rate    and use these data. A. Determine the differential rate law. Be sure to label your plots carefully and show your work. B. Calculate the value of the rate constant k for this reaction at 100°C. C. Calculate [A] and [B] for experiment 1 after 5.00 × 10<sup>2</sup> s has elapsed. D. Which of the following mechanisms could be correct for this reaction? Support your answer.  Let Rate In the reaction 3A(g) + B(g) → 2C(g) + 4D(g) the following data were collected at 100° C.    Let Rate    and use these data. A. Determine the differential rate law. Be sure to label your plots carefully and show your work. B. Calculate the value of the rate constant k for this reaction at 100°C. C. Calculate [A] and [B] for experiment 1 after 5.00 × 10<sup>2</sup> s has elapsed. D. Which of the following mechanisms could be correct for this reaction? Support your answer.  and use these data. A. Determine the differential rate law. Be sure to label your plots carefully and show your work. B. Calculate the value of the rate constant k for this reaction at 100°C. C. Calculate [A] and [B] for experiment 1 after 5.00 × 102 s has elapsed. D. Which of the following mechanisms could be correct for this reaction? Support your answer. In the reaction 3A(g) + B(g) → 2C(g) + 4D(g) the following data were collected at 100° C.    Let Rate    and use these data. A. Determine the differential rate law. Be sure to label your plots carefully and show your work. B. Calculate the value of the rate constant k for this reaction at 100°C. C. Calculate [A] and [B] for experiment 1 after 5.00 × 10<sup>2</sup> s has elapsed. D. Which of the following mechanisms could be correct for this reaction? Support your answer.

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A. Rate = k[A][B]
B. 1.43 × 10-3 L • mol-1 •...

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At a particular temperature, N2O5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration of N2O5 is 1.0 × 1016 molecules/cm3, what will be the concentration in molecules/cm3 after 10.0 s?


A) 6.3 × 103
B) 9.9 × 1014
C) 9.4 × 102
D) 7.3 × 109
E) 1.8 × 1012

F) All of the above
G) B) and D)

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For the reaction in which A and B react to form C, the following initial rate data were obtained. For the reaction in which A and B react to form C, the following initial rate data were obtained.   What is the rate law for the reaction? A)  Rate = k[A]<sup>2</sup>[B]<sup>2</sup> B)  Rate = k[A]<sup>2</sup>[B] C)  Rate = k[A][B]<sup>2</sup> D)  Rate = k[A][B] E)  Rate = k[A]<sup>3</sup> What is the rate law for the reaction?


A) Rate = k[A]2[B]2
B) Rate = k[A]2[B]
C) Rate = k[A][B]2
D) Rate = k[A][B]
E) Rate = k[A]3

F) A) and E)
G) None of the above

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For the reaction 2A + B → products the following mechanism is proposed: A + B For the reaction 2A + B → products the following mechanism is proposed: A + B   M A + M → products Assuming that the second step is the rate-determining step and the first step is a fast equilibrium step, determine the rate law. Represent the rate constant in terms of k<sub>1</sub>, k<sub>-1</sub>, and k<sub>2</sub>. M A + M → products Assuming that the second step is the rate-determining step and the first step is a fast equilibrium step, determine the rate law. Represent the rate constant in terms of k1, k-1, and k2.

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The following questions refer to the reaction 2A2 + B2 → 2C. The mechanism below has been proposed: The following questions refer to the reaction 2A<sub>2</sub> + B<sub>2</sub> → 2C. The mechanism below has been proposed:   -Which step(s)  is(are)  rate-determining? A)  a step that is intermediate between step 1 and step 2 B)  both steps C)  step 2 D)  step 1 E)  none of these -Which step(s) is(are) rate-determining?


A) a step that is intermediate between step 1 and step 2
B) both steps
C) step 2
D) step 1
E) none of these

F) All of the above
G) A) and B)

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Which quantity is greatest?


A) acivation energy of the reverse reaction
B) absolute enthalpy of the reaction
C) activation energy of the forward reaction

D) A) and C)
E) B) and C)

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For the reaction 2N2O5(g) → 4NO2(g) + O2(g) , the following data were collected. For the reaction 2N<sub>2</sub>O<sub>5</sub>(g)  → 4NO<sub>2</sub>(g)  + O<sub>2</sub>(g) , the following data were collected.   -The half-life of this reaction is approximately A)  18 min B)  36 min C)  15 min D)  23 min E)  45 min -The half-life of this reaction is approximately


A) 18 min
B) 36 min
C) 15 min
D) 23 min
E) 45 min

F) D) and E)
G) B) and D)

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Use the potential energy diagram shown to answer the following questions. Use the potential energy diagram shown to answer the following questions.   -Which letter shows the change in energy for the overall reaction? -Which letter shows the change in energy for the overall reaction?

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Tabulated below are initial rate data for the reaction 2Fe(CN) 63- + 2I- → 2Fe(CN) 64- + I2 Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] What is the experimental rate law?


A) Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] k[Fe(CN) 63-][I-]2
B) Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] k[Fe(CN) 63-][I-] [Fe(CN) 64-]
C) Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] k[Fe(CN) 63-]2[I-]
D) Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] k[Fe(CN) 63-]2[I-]2[Fe(CN) 64-]2[I2]
E) Tabulated below are initial rate data for the reaction 2Fe(CN) <sub>6</sub><sup>3-</sup> + 2I<sup>-</sup> → 2Fe(CN) <sub>6</sub><sup>4-</sup> + I<sub>2</sub>   What is the experimental rate law? A)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>]<sup>2</sup> B)    k[Fe(CN) <sub>6</sub><sup>3-</sup>][I<sup>-</sup>] [Fe(CN) <sub>6</sub><sup>4-</sup>] C)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>] D)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[Fe(CN) <sub>6</sub><sup>4-</sup>]<sup>2</sup>[I<sub>2</sub>] E)    k[Fe(CN) <sub>6</sub><sup>3-</sup>]<sup>2</sup>[I<sup>-</sup>][Fe(CN) <sub>6</sub><sup>4-</sup>][I<sub>2</sub>] k[Fe(CN) 63-]2[I-][Fe(CN) 64-][I2]

F) C) and E)
G) A) and E)

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The reaction 3NO → N2O + NO2 Is found to obey the rate law Rate = k[NO]2. If the first half-life of the reaction is found to be 3.5 s, what is the length of the fourth half-life?


A) 21 s
B) 6.6 s
C) 53 s
D) 14 s
E) 56 s

F) B) and E)
G) A) and E)

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How many seconds would it take for the total pressure to be 0.7133 atm?

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Consider the second-order reaction aA → products (which has a first half-life of 25 s) . If the concentration of A after 15.6s is 0.36M, determine the initial concentration of A.


A) 0.58M
B) 0.26M
C) 0.53M
D) 0.14M
E) 0.16M

F) None of the above
G) A) and B)

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